4(5x-2)+3(6-9x)=6(4x+9)-15

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Solution for 4(5x-2)+3(6-9x)=6(4x+9)-15 equation: 



4(5x-2)+3(6-9x)=6(4x+9)-15

We move all terms to the left:

4(5x-2)+3(6-9x)-(6(4x+9)-15)=0

We add all the numbers together, and all the variables

4(5x-2)+3(-9x+6)-(6(4x+9)-15)=0

We multiply parentheses

20x-27x-(6(4x+9)-15)-8+18=0



We calculate terms in parentheses: -(6(4x+9)-15), so:

6(4x+9)-15

We multiply parentheses

24x+54-15

We add all the numbers together, and all the variables

24x+39

Back to the equation:

-(24x+39)



We add all the numbers together, and all the variables

-7x-(24x+39)+10=0

We get rid of parentheses

-7x-24x-39+10=0

We add all the numbers together, and all the variables

-31x-29=0

We move all terms containing x to the left, all other terms to the right

-31x=29

x=29/-31

x=-29/31

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