4(5x+2)=10(2x-3)+15

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Solution for 4(5x+2)=10(2x-3)+15 equation: 



4(5x+2)=10(2x-3)+15

We move all terms to the left:

4(5x+2)-(10(2x-3)+15)=0

We multiply parentheses

20x-(10(2x-3)+15)+8=0



We calculate terms in parentheses: -(10(2x-3)+15), so:

10(2x-3)+15

We multiply parentheses

20x-30+15

We add all the numbers together, and all the variables

20x-15

Back to the equation:

-(20x-15)



We get rid of parentheses

20x-20x+15+8=0

We add all the numbers together, and all the variables

23!=0

There is no solution for this equation

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