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4(5k-5)=3(3k-3)
We move all terms to the left:
4(5k-5)-(3(3k-3))=0
We multiply parentheses
20k-(3(3k-3))-20=0
We calculate terms in parentheses: -(3(3k-3)), so:We get rid of parentheses
3(3k-3)
We multiply parentheses
9k-9
Back to the equation:
-(9k-9)
20k-9k+9-20=0
We add all the numbers together, and all the variables
11k-11=0
We move all terms containing k to the left, all other terms to the right
11k=11
k=11/11
k=1
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