4(5b-8)-7(2+3b)=9-6(b+10)

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Solution for 4(5b-8)-7(2+3b)=9-6(b+10) equation: 



4(5b-8)-7(2+3b)=9-6(b+10)

We move all terms to the left:

4(5b-8)-7(2+3b)-(9-6(b+10))=0

We add all the numbers together, and all the variables

4(5b-8)-7(3b+2)-(9-6(b+10))=0

We multiply parentheses

20b-21b-(9-6(b+10))-32-14=0



We calculate terms in parentheses: -(9-6(b+10)), so:

9-6(b+10)

determiningTheFunctionDomain
-6(b+10)+9

We multiply parentheses

-6b-60+9

We add all the numbers together, and all the variables

-6b-51

Back to the equation:

-(-6b-51)



We add all the numbers together, and all the variables

-1b-(-6b-51)-46=0

We get rid of parentheses

-1b+6b+51-46=0

We add all the numbers together, and all the variables

5b+5=0

We move all terms containing b to the left, all other terms to the right

5b=-5

b=-5/5

b=-1

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