4(5-8(4c-3))=12(1-13c)-8

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Solution for 4(5-8(4c-3))=12(1-13c)-8 equation: 



4(5-8(4c-3))=12(1-13c)-8

We move all terms to the left:

4(5-8(4c-3))-(12(1-13c)-8)=0

We add all the numbers together, and all the variables

4(5-8(4c-3))-(12(-13c+1)-8)=0



We calculate terms in parentheses: -(12(-13c+1)-8), so:

12(-13c+1)-8

We multiply parentheses

-156c+12-8

We add all the numbers together, and all the variables

-156c+4

Back to the equation:

-(-156c+4)



We get rid of parentheses

4(5-8(4c-3))+156c-4=0

We add all the numbers together, and all the variables

156c+4(5-8(4c-3))-4=0

We move all terms containing c to the left, all other terms to the right

156c+4(5-8(4c-3))=4

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