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4(5-2v)=4-8(v-2)
We move all terms to the left:
4(5-2v)-(4-8(v-2))=0
We add all the numbers together, and all the variables
4(-2v+5)-(4-8(v-2))=0
We multiply parentheses
-8v-(4-8(v-2))+20=0
We calculate terms in parentheses: -(4-8(v-2)), so:We get rid of parentheses
4-8(v-2)
determiningTheFunctionDomain -8(v-2)+4
We multiply parentheses
-8v+16+4
We add all the numbers together, and all the variables
-8v+20
Back to the equation:
-(-8v+20)
-8v+8v-20+20=0
We add all the numbers together, and all the variables
=0
v=0/1
v=0
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