4(5+3c)=20

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Solution for 4(5+3c)=20 equation: 



4(5+3c)=20

We move all terms to the left:

4(5+3c)-(20)=0

We add all the numbers together, and all the variables

4(3c+5)-20=0

We multiply parentheses

12c+20-20=0

We add all the numbers together, and all the variables

12c=0

c=0/12

c=0

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