4(5+2n)=4n+3(2n-2)

Solution for 4(5+2n)=4n+3(2n-2) equation:

4(5+2n)=4n+3(2n-2)

We move all terms to the left:

4(5+2n)-(4n+3(2n-2))=0

We add all the numbers together, and all the variables

4(2n+5)-(4n+3(2n-2))=0

We multiply parentheses

8n-(4n+3(2n-2))+20=0


We calculate terms in parentheses: -(4n+3(2n-2)), so:

4n+3(2n-2)

We multiply parentheses

4n+6n-6

We add all the numbers together, and all the variables

10n-6

Back to the equation:

-(10n-6)


We get rid of parentheses

8n-10n+6+20=0

We add all the numbers together, and all the variables

-2n+26=0

We move all terms containing n to the left, all other terms to the right

-2n=-26

n=-26/-2

n=+13