4(4z-3)=3(z-1)+30

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Solution for 4(4z-3)=3(z-1)+30 equation:



4(4z-3)=3(z-1)+30
We move all terms to the left:
4(4z-3)-(3(z-1)+30)=0
We multiply parentheses
16z-(3(z-1)+30)-12=0
We calculate terms in parentheses: -(3(z-1)+30), so:
3(z-1)+30
We multiply parentheses
3z-3+30
We add all the numbers together, and all the variables
3z+27
Back to the equation:
-(3z+27)
We get rid of parentheses
16z-3z-27-12=0
We add all the numbers together, and all the variables
13z-39=0
We move all terms containing z to the left, all other terms to the right
13z=39
z=39/13
z=3

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