4(4z-3)=3(z-1)+3

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Solution for 4(4z-3)=3(z-1)+3 equation: 



4(4z-3)=3(z-1)+3

We move all terms to the left:

4(4z-3)-(3(z-1)+3)=0

We multiply parentheses

16z-(3(z-1)+3)-12=0



We calculate terms in parentheses: -(3(z-1)+3), so:

3(z-1)+3

We multiply parentheses

3z-3+3

We add all the numbers together, and all the variables

3z

Back to the equation:

-(3z)



We add all the numbers together, and all the variables

13z-12=0

We move all terms containing z to the left, all other terms to the right

13z=12

z=12/13

z=12/13

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