4(4z-2)=72

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Solution for 4(4z-2)=72 equation: 



4(4z-2)=72

We move all terms to the left:

4(4z-2)-(72)=0

We multiply parentheses

16z-8-72=0

We add all the numbers together, and all the variables

16z-80=0

We move all terms containing z to the left, all other terms to the right

16z=80

z=80/16

z=5

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