4(4z+1)-6=126

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Solution for 4(4z+1)-6=126 equation:


Simplifying
4(4z + 1) + -6 = 126

Reorder the terms:
4(1 + 4z) + -6 = 126
(1 * 4 + 4z * 4) + -6 = 126
(4 + 16z) + -6 = 126

Reorder the terms:
4 + -6 + 16z = 126

Combine like terms: 4 + -6 = -2
-2 + 16z = 126

Solving
-2 + 16z = 126

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 16z = 126 + 2

Combine like terms: -2 + 2 = 0
0 + 16z = 126 + 2
16z = 126 + 2

Combine like terms: 126 + 2 = 128
16z = 128

Divide each side by '16'.
z = 8

Simplifying
z = 8

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