4(4x-5)=x-35

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Solution for 4(4x-5)=x-35 equation: 



4(4x-5)=x-35

We move all terms to the left:

4(4x-5)-(x-35)=0

We multiply parentheses

16x-(x-35)-20=0

We get rid of parentheses

16x-x+35-20=0

We add all the numbers together, and all the variables

15x+15=0

We move all terms containing x to the left, all other terms to the right

15x=-15

x=-15/15

x=-1

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