4(4x-5)=40+x

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Solution for 4(4x-5)=40+x equation: 



4(4x-5)=40+x

We move all terms to the left:

4(4x-5)-(40+x)=0

We add all the numbers together, and all the variables

4(4x-5)-(x+40)=0

We multiply parentheses

16x-(x+40)-20=0

We get rid of parentheses

16x-x-40-20=0

We add all the numbers together, and all the variables

15x-60=0

We move all terms containing x to the left, all other terms to the right

15x=60

x=60/15

x=4

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