4(4x-3)=6(x-12)+5

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Solution for 4(4x-3)=6(x-12)+5 equation: 



4(4x-3)=6(x-12)+5

We move all terms to the left:

4(4x-3)-(6(x-12)+5)=0

We multiply parentheses

16x-(6(x-12)+5)-12=0



We calculate terms in parentheses: -(6(x-12)+5), so:

6(x-12)+5

We multiply parentheses

6x-72+5

We add all the numbers together, and all the variables

6x-67

Back to the equation:

-(6x-67)



We get rid of parentheses

16x-6x+67-12=0

We add all the numbers together, and all the variables

10x+55=0

We move all terms containing x to the left, all other terms to the right

10x=-55

x=-55/10

x=-5+1/2

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