4(4x-3)+68=17x+204

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Solution for 4(4x-3)+68=17x+204 equation: 



4(4x-3)+68=17x+204

We move all terms to the left:

4(4x-3)+68-(17x+204)=0

We multiply parentheses

16x-(17x+204)-12+68=0

We get rid of parentheses

16x-17x-204-12+68=0

We add all the numbers together, and all the variables

-1x-148=0

We move all terms containing x to the left, all other terms to the right

-x=148

x=148/-1

x=-148

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