4(4x-22)=5(3x-4)

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Solution for 4(4x-22)=5(3x-4) equation: 



4(4x-22)=5(3x-4)

We move all terms to the left:

4(4x-22)-(5(3x-4))=0

We multiply parentheses

16x-(5(3x-4))-88=0



We calculate terms in parentheses: -(5(3x-4)), so:

5(3x-4)

We multiply parentheses

15x-20

Back to the equation:

-(15x-20)



We get rid of parentheses

16x-15x+20-88=0

We add all the numbers together, and all the variables

x-68=0

We move all terms containing x to the left, all other terms to the right

x=68

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