4(4x-2)=-20+4x

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Solution for 4(4x-2)=-20+4x equation: 



4(4x-2)=-20+4x

We move all terms to the left:

4(4x-2)-(-20+4x)=0

We add all the numbers together, and all the variables

4(4x-2)-(4x-20)=0

We multiply parentheses

16x-(4x-20)-8=0

We get rid of parentheses

16x-4x+20-8=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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