4(4x-2)+1=16x-7=

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Solution for 4(4x-2)+1=16x-7= equation: 



4(4x-2)+1=16x-7=

We move all terms to the left:

4(4x-2)+1-(16x-7)=0

We multiply parentheses

16x-(16x-7)-8+1=0

We get rid of parentheses

16x-16x+7-8+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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