4(4x-1)=4(3+1x)

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Solution for 4(4x-1)=4(3+1x) equation: 



4(4x-1)=4(3+1x)

We move all terms to the left:

4(4x-1)-(4(3+1x))=0

We add all the numbers together, and all the variables

4(4x-1)-(4(x+3))=0

We multiply parentheses

16x-(4(x+3))-4=0



We calculate terms in parentheses: -(4(x+3)), so:

4(x+3)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

16x-4x-12-4=0

We add all the numbers together, and all the variables

12x-16=0

We move all terms containing x to the left, all other terms to the right

12x=16

x=16/12

x=1+1/3

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