4(4x-1)=2(2x+2)+(2x)

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Solution for 4(4x-1)=2(2x+2)+(2x) equation: 



4(4x-1)=2(2x+2)+(2x)

We move all terms to the left:

4(4x-1)-(2(2x+2)+(2x))=0

We multiply parentheses

16x-(2(2x+2)+2x)-4=0



We calculate terms in parentheses: -(2(2x+2)+2x), so:

2(2x+2)+2x

We add all the numbers together, and all the variables

2x+2(2x+2)

We multiply parentheses

2x+4x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

16x-6x-4-4=0

We add all the numbers together, and all the variables

10x-8=0

We move all terms containing x to the left, all other terms to the right

10x=8

x=8/10

x=4/5

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