4(4x+3)=19x+9+3x

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Solution for 4(4x+3)=19x+9+3x equation: 



4(4x+3)=19x+9+3x

We move all terms to the left:

4(4x+3)-(19x+9+3x)=0

We add all the numbers together, and all the variables

4(4x+3)-(22x+9)=0

We multiply parentheses

16x-(22x+9)+12=0

We get rid of parentheses

16x-22x-9+12=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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