4(4x+3)=19x+-3+3

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Solution for 4(4x+3)=19x+-3+3 equation: 



4(4x+3)=19x+-3+3

We move all terms to the left:

4(4x+3)-(19x+-3+3)=0

We add all the numbers together, and all the variables

4(4x+3)-(+19x)=0

We multiply parentheses

16x-(+19x)+12=0

We get rid of parentheses

16x-19x+12=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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