4(4x+3)=-4(3x-4)+3x

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Solution for 4(4x+3)=-4(3x-4)+3x equation: 



4(4x+3)=-4(3x-4)+3x

We move all terms to the left:

4(4x+3)-(-4(3x-4)+3x)=0

We multiply parentheses

16x-(-4(3x-4)+3x)+12=0



We calculate terms in parentheses: -(-4(3x-4)+3x), so:

-4(3x-4)+3x

We add all the numbers together, and all the variables

3x-4(3x-4)

We multiply parentheses

3x-12x+16

We add all the numbers together, and all the variables

-9x+16

Back to the equation:

-(-9x+16)



We get rid of parentheses

16x+9x-16+12=0

We add all the numbers together, and all the variables

25x-4=0

We move all terms containing x to the left, all other terms to the right

25x=4

x=4/25

x=4/25

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