4(4x+28)=42x-12

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Solution for 4(4x+28)=42x-12 equation: 



4(4x+28)=42x-12

We move all terms to the left:

4(4x+28)-(42x-12)=0

We multiply parentheses

16x-(42x-12)+112=0

We get rid of parentheses

16x-42x+12+112=0

We add all the numbers together, and all the variables

-26x+124=0

We move all terms containing x to the left, all other terms to the right

-26x=-124

x=-124/-26

x=4+10/13

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