4(4x+1)=19x+1-3x+3

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Solution for 4(4x+1)=19x+1-3x+3 equation: 


Simplifying
4(4x + 1) = 19x + 1 + -3x + 3

Reorder the terms:
4(1 + 4x) = 19x + 1 + -3x + 3
(1 * 4 + 4x * 4) = 19x + 1 + -3x + 3
(4 + 16x) = 19x + 1 + -3x + 3

Reorder the terms:
4 + 16x = 1 + 3 + 19x + -3x

Combine like terms: 1 + 3 = 4
4 + 16x = 4 + 19x + -3x

Combine like terms: 19x + -3x = 16x
4 + 16x = 4 + 16x

Add '-4' to each side of the equation.
4 + -4 + 16x = 4 + -4 + 16x

Combine like terms: 4 + -4 = 0
0 + 16x = 4 + -4 + 16x
16x = 4 + -4 + 16x

Combine like terms: 4 + -4 = 0
16x = 0 + 16x
16x = 16x

Add '-16x' to each side of the equation.
16x + -16x = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 16x + -16x

Combine like terms: 16x + -16x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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