4(4w-3)=8(2w-2)+4

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Solution for 4(4w-3)=8(2w-2)+4 equation: 



4(4w-3)=8(2w-2)+4

We move all terms to the left:

4(4w-3)-(8(2w-2)+4)=0

We multiply parentheses

16w-(8(2w-2)+4)-12=0



We calculate terms in parentheses: -(8(2w-2)+4), so:

8(2w-2)+4

We multiply parentheses

16w-16+4

We add all the numbers together, and all the variables

16w-12

Back to the equation:

-(16w-12)



We get rid of parentheses

16w-16w+12-12=0

We add all the numbers together, and all the variables

=0

w=0/1

w=0

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