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Simplifying 4(4s + 3) = 140 Reorder the terms: 4(3 + 4s) = 140 (3 * 4 + 4s * 4) = 140 (12 + 16s) = 140 Solving 12 + 16s = 140 Solving for variable 's'. Move all terms containing s to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + 16s = 140 + -12 Combine like terms: 12 + -12 = 0 0 + 16s = 140 + -12 16s = 140 + -12 Combine like terms: 140 + -12 = 128 16s = 128 Divide each side by '16'. s = 8 Simplifying s = 8
| 10x-10+2x+3=7x+4-5 | | 11y-6y=35 | | 5x+6+4=10 | | 3(3s+2)=105 | | 5(a-2)=95 | | 8x+5-3x+4=7+3x+6 | | 6x+6+4=11 | | 5(a-4)=90 | | 2(3s+10)=26 | | 6(2l+2)=60 | | 1.5x+12=6x+40 | | 7(3s+6)=168 | | 3(2l+1)=21 | | 5(a-7)=10 | | -3(2t+10)=-60 | | 10(s-10)=-152 | | 4(f-1)=28 | | -2x+5y=27 | | 11.6=1.5(x-3.5) | | 14=1.5(x-3.5) | | y=-16(6)+52(6)+48 | | y=-16(5)+52(5)+48 | | y=-16(4)+52(4)+48 | | y=-16(3)+52(3)+48 | | y=-16(2)+52(2)+48 | | -2x^2-12x-19=0 | | 8c^3+22c^2+15c=0 | | y=-16(1)+52(1)+48 | | 7(3)+2(3(3)-11)=17 | | 2cx-ca-bx+2ab-cb-ax=2(c-a)(c-b) | | y=-16(0)+52(0)+48 | | a(x+a)+b(x+b)+2ab=0 |