4(4r+2)+5(6r+5)=7r+6r

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Solution for 4(4r+2)+5(6r+5)=7r+6r equation: 



4(4r+2)+5(6r+5)=7r+6r

We move all terms to the left:

4(4r+2)+5(6r+5)-(7r+6r)=0

We add all the numbers together, and all the variables

4(4r+2)+5(6r+5)-(+13r)=0

We multiply parentheses

16r+30r-(+13r)+8+25=0

We get rid of parentheses

16r+30r-13r+8+25=0

We add all the numbers together, and all the variables

33r+33=0

We move all terms containing r to the left, all other terms to the right

33r=-33

r=-33/33

r=-1

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