4(4d-5)=35

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Solution for 4(4d-5)=35 equation: 



4(4d-5)=35

We move all terms to the left:

4(4d-5)-(35)=0

We multiply parentheses

16d-20-35=0

We add all the numbers together, and all the variables

16d-55=0

We move all terms containing d to the left, all other terms to the right

16d=55

d=55/16

d=3+7/16

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