4(4b-3)+6b=4(6b+4)-10

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Solution for 4(4b-3)+6b=4(6b+4)-10 equation: 



4(4b-3)+6b=4(6b+4)-10

We move all terms to the left:

4(4b-3)+6b-(4(6b+4)-10)=0

We add all the numbers together, and all the variables

6b+4(4b-3)-(4(6b+4)-10)=0

We multiply parentheses

6b+16b-(4(6b+4)-10)-12=0



We calculate terms in parentheses: -(4(6b+4)-10), so:

4(6b+4)-10

We multiply parentheses

24b+16-10

We add all the numbers together, and all the variables

24b+6

Back to the equation:

-(24b+6)



We add all the numbers together, and all the variables

22b-(24b+6)-12=0

We get rid of parentheses

22b-24b-6-12=0

We add all the numbers together, and all the variables

-2b-18=0

We move all terms containing b to the left, all other terms to the right

-2b=18

b=18/-2

b=-9

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