4(4b+3)=5(4b-4)

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Solution for 4(4b+3)=5(4b-4) equation: 



4(4b+3)=5(4b-4)

We move all terms to the left:

4(4b+3)-(5(4b-4))=0

We multiply parentheses

16b-(5(4b-4))+12=0



We calculate terms in parentheses: -(5(4b-4)), so:

5(4b-4)

We multiply parentheses

20b-20

Back to the equation:

-(20b-20)



We get rid of parentheses

16b-20b+20+12=0

We add all the numbers together, and all the variables

-4b+32=0

We move all terms containing b to the left, all other terms to the right

-4b=-32

b=-32/-4

b=+8

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