4(4b+3)+2b=3(b-11)

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Solution for 4(4b+3)+2b=3(b-11) equation:



4(4b+3)+2b=3(b-11)
We move all terms to the left:
4(4b+3)+2b-(3(b-11))=0
We add all the numbers together, and all the variables
2b+4(4b+3)-(3(b-11))=0
We multiply parentheses
2b+16b-(3(b-11))+12=0
We calculate terms in parentheses: -(3(b-11)), so:
3(b-11)
We multiply parentheses
3b-33
Back to the equation:
-(3b-33)
We add all the numbers together, and all the variables
18b-(3b-33)+12=0
We get rid of parentheses
18b-3b+33+12=0
We add all the numbers together, and all the variables
15b+45=0
We move all terms containing b to the left, all other terms to the right
15b=-45
b=-45/15
b=-3

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