4(41+a)=12

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Solution for 4(41+a)=12 equation: 



4(41+a)=12

We move all terms to the left:

4(41+a)-(12)=0

We add all the numbers together, and all the variables

4(a+41)-12=0

We multiply parentheses

4a+164-12=0

We add all the numbers together, and all the variables

4a+152=0

We move all terms containing a to the left, all other terms to the right

4a=-152

a=-152/4

a=-38

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