4(41+a)=102

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Solution for 4(41+a)=102 equation: 



4(41+a)=102

We move all terms to the left:

4(41+a)-(102)=0

We add all the numbers together, and all the variables

4(a+41)-102=0

We multiply parentheses

4a+164-102=0

We add all the numbers together, and all the variables

4a+62=0

We move all terms containing a to the left, all other terms to the right

4a=-62

a=-62/4

a=-15+1/2

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