4(4-2x)+2x=1-3(2+3x)

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Solution for 4(4-2x)+2x=1-3(2+3x) equation: 



4(4-2x)+2x=1-3(2+3x)

We move all terms to the left:

4(4-2x)+2x-(1-3(2+3x))=0

We add all the numbers together, and all the variables

4(-2x+4)+2x-(1-3(3x+2))=0

We add all the numbers together, and all the variables

2x+4(-2x+4)-(1-3(3x+2))=0

We multiply parentheses

2x-8x-(1-3(3x+2))+16=0



We calculate terms in parentheses: -(1-3(3x+2)), so:

1-3(3x+2)

determiningTheFunctionDomain
-3(3x+2)+1

We multiply parentheses

-9x-6+1

We add all the numbers together, and all the variables

-9x-5

Back to the equation:

-(-9x-5)



We add all the numbers together, and all the variables

-6x-(-9x-5)+16=0

We get rid of parentheses

-6x+9x+5+16=0

We add all the numbers together, and all the variables

3x+21=0

We move all terms containing x to the left, all other terms to the right

3x=-21

x=-21/3

x=-7

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