4(4+2x)=3(3+3x+1)

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Solution for 4(4+2x)=3(3+3x+1) equation: 



4(4+2x)=3(3+3x+1)

We move all terms to the left:

4(4+2x)-(3(3+3x+1))=0

We add all the numbers together, and all the variables

4(2x+4)-(3(3x+4))=0

We multiply parentheses

8x-(3(3x+4))+16=0



We calculate terms in parentheses: -(3(3x+4)), so:

3(3x+4)

We multiply parentheses

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

8x-9x-12+16=0

We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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