4(3z-2)=-(-10z+20)

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Solution for 4(3z-2)=-(-10z+20) equation: 



4(3z-2)=-(-10z+20)

We move all terms to the left:

4(3z-2)-(-(-10z+20))=0

We multiply parentheses

12z-(-(-10z+20))-8=0



We calculate terms in parentheses: -(-(-10z+20)), so:

-(-10z+20)

We get rid of parentheses

10z-20

Back to the equation:

-(10z-20)



We get rid of parentheses

12z-10z+20-8=0

We add all the numbers together, and all the variables

2z+12=0

We move all terms containing z to the left, all other terms to the right

2z=-12

z=-12/2

z=-6

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