4(3z-1)-3(z+4)=5(z+1)

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Solution for 4(3z-1)-3(z+4)=5(z+1) equation:


Simplifying
4(3z + -1) + -3(z + 4) = 5(z + 1)

Reorder the terms:
4(-1 + 3z) + -3(z + 4) = 5(z + 1)
(-1 * 4 + 3z * 4) + -3(z + 4) = 5(z + 1)
(-4 + 12z) + -3(z + 4) = 5(z + 1)

Reorder the terms:
-4 + 12z + -3(4 + z) = 5(z + 1)
-4 + 12z + (4 * -3 + z * -3) = 5(z + 1)
-4 + 12z + (-12 + -3z) = 5(z + 1)

Reorder the terms:
-4 + -12 + 12z + -3z = 5(z + 1)

Combine like terms: -4 + -12 = -16
-16 + 12z + -3z = 5(z + 1)

Combine like terms: 12z + -3z = 9z
-16 + 9z = 5(z + 1)

Reorder the terms:
-16 + 9z = 5(1 + z)
-16 + 9z = (1 * 5 + z * 5)
-16 + 9z = (5 + 5z)

Solving
-16 + 9z = 5 + 5z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-5z' to each side of the equation.
-16 + 9z + -5z = 5 + 5z + -5z

Combine like terms: 9z + -5z = 4z
-16 + 4z = 5 + 5z + -5z

Combine like terms: 5z + -5z = 0
-16 + 4z = 5 + 0
-16 + 4z = 5

Add '16' to each side of the equation.
-16 + 16 + 4z = 5 + 16

Combine like terms: -16 + 16 = 0
0 + 4z = 5 + 16
4z = 5 + 16

Combine like terms: 5 + 16 = 21
4z = 21

Divide each side by '4'.
z = 5.25

Simplifying
z = 5.25

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