4(3z-1)-3(z+2)=4(z+1)

Solution for 4(3z-1)-3(z+2)=4(z+1) equation:

Simplifying
4(3z + -1) + -3(z + 2) = 4(z + 1)

Reorder the terms:
4(-1 + 3z) + -3(z + 2) = 4(z + 1)
(-1 * 4 + 3z * 4) + -3(z + 2) = 4(z + 1)
(-4 + 12z) + -3(z + 2) = 4(z + 1)

Reorder the terms:
-4 + 12z + -3(2 + z) = 4(z + 1)
-4 + 12z + (2 * -3 + z * -3) = 4(z + 1)
-4 + 12z + (-6 + -3z) = 4(z + 1)

Reorder the terms:
-4 + -6 + 12z + -3z = 4(z + 1)

Combine like terms: -4 + -6 = -10
-10 + 12z + -3z = 4(z + 1)

Combine like terms: 12z + -3z = 9z
-10 + 9z = 4(z + 1)

Reorder the terms:
-10 + 9z = 4(1 + z)
-10 + 9z = (1 * 4 + z * 4)
-10 + 9z = (4 + 4z)

Solving
-10 + 9z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-10 + 9z + -4z = 4 + 4z + -4z

Combine like terms: 9z + -4z = 5z
-10 + 5z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-10 + 5z = 4 + 0
-10 + 5z = 4

Add '10' to each side of the equation.
-10 + 10 + 5z = 4 + 10

Combine like terms: -10 + 10 = 0
0 + 5z = 4 + 10
5z = 4 + 10

Combine like terms: 4 + 10 = 14
5z = 14

Divide each side by '5'.
z = 2.8

Simplifying
z = 2.8