4(3z+4)+9=47

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Solution for 4(3z+4)+9=47 equation: 



4(3z+4)+9=47

We move all terms to the left:

4(3z+4)+9-(47)=0

We add all the numbers together, and all the variables

4(3z+4)-38=0

We multiply parentheses

12z+16-38=0

We add all the numbers together, and all the variables

12z-22=0

We move all terms containing z to the left, all other terms to the right

12z=22

z=22/12

z=1+5/6

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