4(3z+2)=4-2(z-2)

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Solution for 4(3z+2)=4-2(z-2) equation:


Simplifying
4(3z + 2) = 4 + -2(z + -2)

Reorder the terms:
4(2 + 3z) = 4 + -2(z + -2)
(2 * 4 + 3z * 4) = 4 + -2(z + -2)
(8 + 12z) = 4 + -2(z + -2)

Reorder the terms:
8 + 12z = 4 + -2(-2 + z)
8 + 12z = 4 + (-2 * -2 + z * -2)
8 + 12z = 4 + (4 + -2z)

Combine like terms: 4 + 4 = 8
8 + 12z = 8 + -2z

Add '-8' to each side of the equation.
8 + -8 + 12z = 8 + -8 + -2z

Combine like terms: 8 + -8 = 0
0 + 12z = 8 + -8 + -2z
12z = 8 + -8 + -2z

Combine like terms: 8 + -8 = 0
12z = 0 + -2z
12z = -2z

Solving
12z = -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
12z + 2z = -2z + 2z

Combine like terms: 12z + 2z = 14z
14z = -2z + 2z

Combine like terms: -2z + 2z = 0
14z = 0

Divide each side by '14'.
z = 0

Simplifying
z = 0

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