4(3y-5)=-2(-6y+10)

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Solution for 4(3y-5)=-2(-6y+10) equation: 



4(3y-5)=-2(-6y+10)

We move all terms to the left:

4(3y-5)-(-2(-6y+10))=0

We multiply parentheses

12y-(-2(-6y+10))-20=0



We calculate terms in parentheses: -(-2(-6y+10)), so:

-2(-6y+10)

We multiply parentheses

12y-20

Back to the equation:

-(12y-20)



We get rid of parentheses

12y-12y+20-20=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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