4(3y-4)=2(4y-6)

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Solution for 4(3y-4)=2(4y-6) equation: 



4(3y-4)=2(4y-6)

We move all terms to the left:

4(3y-4)-(2(4y-6))=0

We multiply parentheses

12y-(2(4y-6))-16=0



We calculate terms in parentheses: -(2(4y-6)), so:

2(4y-6)

We multiply parentheses

8y-12

Back to the equation:

-(8y-12)



We get rid of parentheses

12y-8y+12-16=0

We add all the numbers together, and all the variables

4y-4=0

We move all terms containing y to the left, all other terms to the right

4y=4

y=4/4

y=1

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