4(3y+5)+y=6(2y+3)

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Solution for 4(3y+5)+y=6(2y+3) equation: 



4(3y+5)+y=6(2y+3)

We move all terms to the left:

4(3y+5)+y-(6(2y+3))=0

We add all the numbers together, and all the variables

y+4(3y+5)-(6(2y+3))=0

We multiply parentheses

y+12y-(6(2y+3))+20=0



We calculate terms in parentheses: -(6(2y+3)), so:

6(2y+3)

We multiply parentheses

12y+18

Back to the equation:

-(12y+18)



We add all the numbers together, and all the variables

13y-(12y+18)+20=0

We get rid of parentheses

13y-12y-18+20=0

We add all the numbers together, and all the variables

y+2=0

We move all terms containing y to the left, all other terms to the right

y=-2

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