4(3y+2)=2(2y-1)

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Solution for 4(3y+2)=2(2y-1) equation: 



4(3y+2)=2(2y-1)

We move all terms to the left:

4(3y+2)-(2(2y-1))=0

We multiply parentheses

12y-(2(2y-1))+8=0



We calculate terms in parentheses: -(2(2y-1)), so:

2(2y-1)

We multiply parentheses

4y-2

Back to the equation:

-(4y-2)



We get rid of parentheses

12y-4y+2+8=0

We add all the numbers together, and all the variables

8y+10=0

We move all terms containing y to the left, all other terms to the right

8y=-10

y=-10/8

y=-1+1/4

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