4(3y+10)+2=10y+5-2

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Solution for 4(3y+10)+2=10y+5-2 equation: 



4(3y+10)+2=10y+5-2

We move all terms to the left:

4(3y+10)+2-(10y+5-2)=0

We add all the numbers together, and all the variables

4(3y+10)-(10y+3)+2=0

We multiply parentheses

12y-(10y+3)+40+2=0

We get rid of parentheses

12y-10y-3+40+2=0

We add all the numbers together, and all the variables

2y+39=0

We move all terms containing y to the left, all other terms to the right

2y=-39

y=-39/2

y=-19+1/2

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