4(3y+1)-3(2y-5)=29

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Solution for 4(3y+1)-3(2y-5)=29 equation: 



4(3y+1)-3(2y-5)=29

We move all terms to the left:

4(3y+1)-3(2y-5)-(29)=0

We multiply parentheses

12y-6y+4+15-29=0

We add all the numbers together, and all the variables

6y-10=0

We move all terms containing y to the left, all other terms to the right

6y=10

y=10/6

y=1+2/3

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