4(3x-8)=11(x-2)

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Solution for 4(3x-8)=11(x-2) equation: 



4(3x-8)=11(x-2)

We move all terms to the left:

4(3x-8)-(11(x-2))=0

We multiply parentheses

12x-(11(x-2))-32=0



We calculate terms in parentheses: -(11(x-2)), so:

11(x-2)

We multiply parentheses

11x-22

Back to the equation:

-(11x-22)



We get rid of parentheses

12x-11x+22-32=0

We add all the numbers together, and all the variables

x-10=0

We move all terms containing x to the left, all other terms to the right

x=10

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