4(3x-8)=(2x-5)

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Solution for 4(3x-8)=(2x-5) equation: 



4(3x-8)=(2x-5)

We move all terms to the left:

4(3x-8)-((2x-5))=0

We multiply parentheses

12x-((2x-5))-32=0



We calculate terms in parentheses: -((2x-5)), so:

(2x-5)

We get rid of parentheses

2x-5

Back to the equation:

-(2x-5)



We get rid of parentheses

12x-2x+5-32=0

We add all the numbers together, and all the variables

10x-27=0

We move all terms containing x to the left, all other terms to the right

10x=27

x=27/10

x=2+7/10

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